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Using the TI85 |
| Goal: |
| Find the Minimum Value of f (x)=x2 2x. |
| Graph f (x)=x2 2x in the Range Xmin = 4, Xmax = 4, Ymin = 6 and Ymax = 10. |
| Procedure: |
| Select More from the Graph menus followed by Math. |
| Select lower. Move cursor to the left of lowest point on graph. |
| Press Enter. See arrow top of screen. |
| Press Upper. Move cursor to the right of lowest point on graph. |
| Press Enter. See arrow top of screen on the right side of the other arrow. |
| Press More and find Fmin. Select Fmin. Move cursor to lowest point . |
| Press Enter. Should see x = 0.99999991219 and y = 1. Make sure the float is over the 0 or the 2nd 1. You can change the float by going to 2nd More (Mode). |
| The minimum value of f (x) is 1, the yvalue. |
| Goal: |
| Find the Maximum Value of f (x)= x2 2x. |
| Graph f (x) in the window Xmin = 4, Xmax = 4, Ymin = 6 and Ymax = 6. |
| Procedure: |
| Select More from the Graph menus followed by Math. |
| Select lower. Move cursor to the left of highest point on graph. |
| Press Enter. See arrow top of screen. |
| Press Upper. Move cursor to the right of highest point on graph. |
| Press Enter. See arrow top of screen on the right side of the other arrow. |
| Press More and find Fmax. Select Fmax. Move cursor to highest point. |
| Press Enter. Should see x = 0.9999988942 and y = 1. |
| The maximum value of f (x) is 1, the y-value. |
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